I've seen folks like Chuck Hawk say that you should consider about 1500 ft lbs of energy the minimum to cleanly kill an elk for the average shooter (and 800 for whitetail). Now that's gonna be contested by everyone that's shot an elk with a 30/30 at more than 50 yards, but he's talking with what is available today there is no reason to accept less than this and the average shooter is not good at estimating distance and therefore bullet drop/windage, soooo to compensate use a fast flat shooting round that will expand well and kill cleanly. That way you take some of the uncertainty away. Totally agree with that sentiment...but...can you do it with less than 1500? Absolutely. And if you are more experienced at estimating ranges and calculating drop and windage, shoot a lot to establish this ability, know the current conditions, have the ability to properly place the bullet, and have a bullet that is designed for the velocity that it will be at when it strikes the target (may mean carrying 3 or 4 different types of ammo and not loading until you know which type shot you're going to get) you can pull it off. Can I? NOPE, and I don't care to try to take all this into account. I'll just get a little closer and remove the uncertainty vice trying to make a low percentage shot, and I'm going to use a faster round to do it.
So how does this relate to the 7.62X39? What type/grain bullet at what muzzle velocity? Put it in a ballistic calculater like the one at
www.realguns.com and figure out your energy and drop. Then comes the subjective part, where are your limits? Can you estimate accurately the wind speed and bullet drop at 200 yards and hit a six inch circle every time? Maybe you can take that shot. If you're only talking hitting targets, then effective range is directly propertional to your abilities. I'm reminded of the warning inside a 22lr box, "Danger: range over 1 mile" yeah, but could you accurately hit anything with a 22 at 2000yds? :grin:
Helicopter Bill